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23w^2-47w=0
a = 23; b = -47; c = 0;
Δ = b2-4ac
Δ = -472-4·23·0
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-47}{2*23}=\frac{0}{46} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+47}{2*23}=\frac{94}{46} =2+1/23 $
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